We are told that A = (7 2, -4 1) has eigenvalues 5 and 3 with respective eigenvectors (1, -1) and (1, -2). So we can diagonalise A by finding an invertible matrix M and diagonal matrix D such that M^-1AM = D.
i) If we wanted D to be the matrix D = (5 0, 0 3) then we should take M = <<1|1>,<-1|-2>>.
ii) If instead we wanted D to be the diagonal matrix D = (3 0, 0 5) then we should take M = <<1|1>,<-2|-1>>.
iii) One of the advantages of having a diagonal matrix is that matrix powers are easy to take, for example (5 0, 0 3)^6 = <<15625|0>,<0|729>>.
The relation for A^n is not nearly as simple.
iv) Once we write A = MDM^-1 we observe that A^2 = MD^2M^-1, A^3 = MD^3M^-1, and so on. Thus, using parts (i) and (iii), we can easily calculate that the top left entry of A^6 is.
Recall: the Maple notation for the matrix (1 2, 3 4) is <<1|2>,<3|4>>.