00:01
In this question, we need to find the formula for the general term an of the sequence 2 by 1, 4 by 3, 6 by 5, 8 by 7 and so on.
00:22
Also, we are required to determine whether the sequence converges and if it converges then we need to find its limit.
00:30
Let's see how to solve this question.
00:32
The fraction 2 by 1 can be written as 2 multiplied by 1 upon 2 multiplied by 1 minus 1.
00:47
So this will be equal to 2 by 1.
00:50
The fraction 4 by 3 can be written as 2 multiplied by 2 upon 2 multiplied by 2 minus 1 and this will be equals to 4 by 3.
01:03
Similarly, 6x by 5 can be written as 2 multiplied by 3 upon 2 multiplied by 3 minus 1 and this will be equals to 6 upon 5.
01:17
Now let's move to the fraction 8 by 7.
01:21
8 by 7 will be equal to 2 multiplied by 4 upon 2 multiplied by 4 minus 1 and this will be equal to 8 by 7.
01:30
In this manner when we continue, so finally we get the nth term, a .n is equals to 2 into n upon 2 multiplied by n minus 1...