We have the following. 56 = (A + 8B)x + (A + B) We must now...

We have the following. 56 = (A + 8B)x + (A + B) We must now determine the values of A and B. There is no x-term on the left side of the equation, which tells us that the coef A + 8B = 0 Setting the constant on the left side of the equation equal to the constant on t = A + B Subtracting the second equation from the first allows us to determine B. B = Substituting this value of B into either of the equations allows us to solve for A. A =

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We have the following: 56 = (A + 8B)x + (A + B) We must now determine the values of A and B. There is no x-term on the left side of the equation, which tells us that the coefficient of x is 0. A + 8B = 0 Setting the constant on the left side of the equation equal to the constant on the right side: A + B = 56 Subtracting the second equation from the first allows us to determine B. B = 7 Substituting this value of B into either of the equations allows us to solve for A. A = -56 We have the following: 56 = A + 8B x A + B We must now determine the values of A and B. There is no x-term on the left side of the equation, which tells us that the coefficient of x is 0. A + 8B = 0 Setting the constant on the left side of the equation equal to the constant on the right side: A + B = 56 Subtracting the second equation from the first allows us to determine B. B = 7 Substituting this value of B into either of the equations allows us to solve for A. A = -56

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