What fraction of 5 MeV α particles will be scattered through angles greater than 7° from a gold foil (Z = 79, density = 19.3 g/cm³) of thickness 10⁻⁸ m?
Added by Francisca C.
Step 1
First, we need to find the number of atoms per unit volume in the gold foil. We know the density of gold (ρ) is 19.3 g/cm³, and the atomic mass of gold (Au) is 197 g/mol. We can use Avogadro's number (N_A = 6.022 x 10²³ atoms/mol) to find the number of atoms per Show more…
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