Question

4. What is a formula for the second derivative of f(t) = t^2 sin 2t? Use this formula to compute f"(?/2). f"(t) = -8 sin 2t, and f"(?/2) = 0 f"(t) = 8t cos 2t + (2 - 4t^2) sin 2t, and f"(?/2) = -4? f"(t) = 4t cos 2t, and f"(?/2) = -2? f"(t) = -4t^2 sin 2t, and f"(?/2) = 0 f"(t) = 8t cos 2t – 4t^2 sin 2t, and f"(?/2) = -4? f"(t) = 4t cos 2t + (2 - 4t^2) sin 2t, and f"(?/2) = -2?

          4. What is a formula for the second derivative of f(t) = t^2 sin 2t? Use this formula to compute f"(?/2).
f"(t) = -8 sin 2t, and f"(?/2) = 0
f"(t) = 8t cos 2t + (2 - 4t^2) sin 2t, and f"(?/2) = -4?
f"(t) = 4t cos 2t, and f"(?/2) = -2?
f"(t) = -4t^2 sin 2t, and f"(?/2) = 0
f"(t) = 8t cos 2t – 4t^2 sin 2t, and f"(?/2) = -4?
f"(t) = 4t cos 2t + (2 - 4t^2) sin 2t, and f"(?/2) = -2?

4. What is a formula for the second derivative of f(t) = t^2 sin 2t? Use this formula to compute f"(?/2).
f"(t) = -8 sin 2t, and f"(?/2) = 0
f"(t) = 8t cos 2t + (2 - 4t^2) sin 2t, and f"(?/2) = -4?
f"(t) = 4t cos 2t, and f"(?/2) = -2?
f"(t) = -4t^2 sin 2t, and f"(?/2) = 0
f"(t) = 8t cos 2t – 4t^2 sin 2t, and f"(?/2) = -4?
f"(t) = 4t cos 2t + (2 - 4t^2) sin 2t, and f"(?/2) = -2?

Added by Tiffany M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert William Semus

05/16/2022

Step 1

Step 1:** Find the first derivative of \(f(t) = t^2 \sin(2t)\): \[f'(t) = 2t \sin(2t) + t^2 \cdot 2 \cos(2t) = 2t \sin(2t) + 2t^2 \cos(2t)\] ** Show more…

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What is a formula for the second derivative of f(t) = t^2 sin 2t? Use this formula to compute f"(π/2). f"(t) = -8 sin 2t, and f"(π/2) = 0 f"(t) = 8t cos 2t + (2 - 4t^2) sin 2t, and f"(π/2) = -4π f"(t) = 4t cos 2t, and f"(π/2) = -2π f"(t) = -4t^2 sin 2t, and f"(π/2) = 0 f"(t) = 8t cos 2t - 4t^2 sin 2t, and f"(π/2) = -4π f"(t) = 4t cos 2t + (2 - 4t^2) sin 2t, and f"(π/2) = -2π