What is the centripetal acceleration of the Moon? The period of the Moon's orbit about the Earth is 27.3 days, measured with respect to the fixed stars. The radius of the Moon's orbit is RM = 3.85 x 10^8 m.
Added by Raven R.
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We need to convert the period of the Moon's orbit from days to seconds. There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. So, we have: $$ T = 27.3 \text{ days} \times \frac{24 \text{ hours}}{1 \text{ day}} \times \frac{60 \text{ Show more…
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Find the centripetal acceleration of the moon toward the earth, assuming that the orbit of the moon is a circle of neclius 239,000 miles $=3.85 \cdot 10^{8} \mathrm{m},$ and the time for one complete revolution is 27.3 days $=2.36 \cdot 10^{6} \mathrm{sec}$
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The moon completes one (circular) orbit of the earth in 27.3 days. The distance from the earth to the moon is $3.84 \times 10^{8} \mathrm{m} .$ What is the moon's centripetal acceleration?
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