00:01
Hi to everyone, so here the general master theorem formula is pn a pn by b plus f by f into n.
00:14
The age number of the problem b is the factor by which input size is reduced.
00:19
Fn is the time it takes.
00:21
So first one is pn 2t n by 2 plus 1.
00:27
Okay, so here a is equal to 2, b is equal to 2 and fn equals to 1.
00:34
Since fn is equal to 0, n to the power 0, it falls in case 1 of master theorem.
00:45
The solution is solution form is pn n to the power of n log 2 log e 2 plus 2 minus n.
01:01
The o notation, this is o n.
01:07
Now into pn 2t n by 2 plus n.
01:16
A is equal to 2, b is equal to 2 and fn is equal to n...