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Good day.
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In this question, we will be solving for the empirical formula of the given compound with the percent composition.
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So assuming 100 grams, therefore, we will have 28 .03 grams calcium, 49 .59 grams of chlorine, and 22 .38 grams of oxygen.
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Next, we need to solve for moles of each element, where moles of each element is equal to the mass divided by molar mass.
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So, mole of calcium is 28 .03 grams divided by 40 .08 grams per mole is equals to 0 .699 mole.
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Mole of cl equals 49 .59 grams divided by 355 grams per month.
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This is equals to 1 .399 mole.
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Next mole of 0 is equal to 22 .38 grams divided by 16 grams per mole.
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This is 1 .399 mole also...