00:01
Hello students, let's begin with this question.
00:02
This question is based upon the depression in the freezing point.
00:07
So, in the question some data is provided and we have to find out the freezing point of magnesium bromide.
00:13
So, firstly the formula used here is so delta tf is equals to van der vector i into kf.
00:20
This kf is the freezing point constant multiply molality.
00:23
So, this delta tf is equals to this is the temperature of pure water minus the this is the freezing temperature of the pure water minus the freezing temperature of the substance.
00:47
Now, in the question firstly this mgbr2 is given.
00:54
So, this will dissociate to form mg2 positive plus 2 br negative.
01:00
So, from here the van der vector i is equals to 1 plus 2.
01:03
So, this is equals to 3 and in the question the molality value is given which is equals to 1 .78 molal and the kf this is the freezing point constant its value is 1 .86 degree celsius per molal...