00:01
Hello student, in this question we are given 1 .58 molar nscl and we need to calculate its freezing point.
00:13
The value of kf for water is given as 1 .869.
00:19
So we know that the value of delta tf, that is the change in freezing point, is given as i multiplied by kf multiplied by molality.
00:31
So for nacl if we calculate i, that is the vant of factor.
00:39
So nacl dissociates into na plus and cl minus.
00:44
So number of ions into which it is dissociating is 1 and 1.
00:48
So the value of i will be equal to 1 plus 1 which is equal to 2.
00:53
So form here if we substitute the value we will get delta tf is equal to 2, multiplied by value of kf which is 1 .86, multiplied by mulali.
01:04
Which is given as 1 .5...