What is the mass of lead(II) iodide produced from 1.0 g of potassium iodide and excess lead(II) nitrate? Pb(NO$_3$)$_2$(aq) + 2 KI(s) -> PbI$_2$(s) + 2 KNO$_3$(aq)
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The molar mass of KI is: $39.10 \text{ g/mol} + 126.90 \text{ g/mol} = 166.00 \text{ g/mol}$ The molar mass of PbI2 is: $207.2 \text{ g/mol} + 2(126.90 \text{ g/mol}) = 461.0 \text{ g/mol}$ Show more…
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