00:01
Hello, my name is john, and for this question, what is the molality of phosphoric acid, which is h3po4, in a solution of 14 .5 grams of h3 p .o4 in 125 grams of water? so, first, we have to define the equation or formula for malality, and molality by definition, is equal to the amount of moles of the solute, and in this particular scenario, that is, h3 -p -o -4 over the amount of kilograms of the solvent.
00:42
And in this case, the solvent is water.
00:46
So going by this, let's first determine the amount of kilograms of solvent.
00:50
We have 125 grams of water.
00:54
And by conversion, this is equal to 0 .1 ,25 kilograms of h -2 -0.
01:01
Next, we have 14 .5 grams of the solute, which is h3p4, and we're going to use its molar mass to convert it to its amount of moles.
01:18
And if you search up the molar mass for h3po4, it is 97 .99 grams.
01:27
So that means for every one mole of h3p04, it weighs 97 .8...