Question
What is the molarity of a solution made by dissolving $0.583 \mathrm{g}$ of the diprotic acid oxalic acid, $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},$ in enough water to make $1.75 \mathrm{L}$ of solution?
Step 1
The molar mass of hydrogen (H) is approximately 1 g/mol, carbon (C) is approximately 12 g/mol, and oxygen (O) is approximately 16 g/mol. Therefore, the molar mass of oxalic acid is $2(1) + 2(12) + 4(16) = 90 \mathrm{g/mol}$. Show more…
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A solution is prepared by dissolving 0.6706 g oxalic acid $\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)$ in enough water to make 100.0 $\mathrm{mL}$ of solution. A 10.00-mL aliquot (portion) of this solution is then diluted to a final volume of 250.0 mL. What is the final molarity of the oxalic acid solution?
A solution is prepared by dissolving 0.6706 g oxalic acid $\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)$ in enough water to make $100.0 \mathrm{mL}$ of solution. $\mathrm{A}$ $10.00-\mathrm{mL}$ aliquot (portion) of this solution is then diluted to a final volume of $250.0 \mathrm{mL}$. What is the final molarity of the oxalic acid solution?
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