The distance is 1 m and the angle is 30 degrees.
$$ \tau_1 = r_1 F_1 \sin(\theta_1) = (1 \text{ m})(100 \text{ N})\sin(30^\circ) = 100 \text{ N m} \times 0.5 = 50 \text{ N m} $$
The torque is clockwise, so it is negative.
$$ \tau_1 = -50 \text{ N m} $$
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