00:01
Question what is the percent yield of a reaction in which 200 gram of phosphorus trichloride react with excess water to form 102 gram of xl and aqueous phosphorus acid so let us see the reaction in which phosphorus trichloride react with excess of water to produce h3 p .o3 which is known as phosphorous acid along with hcl right so.
00:31
So now let us balance this reaction.
00:35
So here i'm using the stochometric coefficient 3 in water and the stochometric coefficient 3 in hcl so that the equation is balanced.
00:44
So phosphorus trichloride so i can say one mole of phosphorus trichloride react with the 3 mol of excess of water to form hydrochloric acid to form 3 mol of hydrochloric acid and 1 mole of phosphorus acid in this balanced reaction.
01:02
So now let us see what we have given.
01:04
We have given the mass of phosphorus trichloride which is 200 gram and we know molar mass of phosphorus trich chloride which is 137 .33 gram per mole.
01:13
The actual yield of hydrochloric acid that is 102 gram.
01:19
This is given in the question and we have to find the percent yield of the reaction.
01:27
So let us first find out the number of the number of the reaction.
01:28
So let us first find out the number of moles so number of moles can be calculated by using this formula mass upon molar mass so number of moles of phosphorus trichloride that is equal to mass of phosphorus trichloride upon molar mass of phosphorus trichloride so substitute the value and we get the moles of phosphorous chloride which is 1 .456 moles of phosphorus trichloride now we apply the talkometry here so you can see one mole of phosphorus trichloride will produce 3 mol of hcl...