What is the pH of the solution formed by mixing 25.0 mL of a 0.15 M solution of NH3 with 25.0 mL of 0.12 M HCl? (Kb for NH3 = 1.8 × 10^(-5)) (A) 4.14 (B) 5.34 (C) 8.65 (D) 9.86
Added by Mike B.
Step 1
First, we need to find the moles of NH3 and HCl in the solution. moles of NH3 = 0.15 M * 0.025 L = 0.00375 mol moles of HCl = 0.12 M * 0.025 L = 0.00300 mol Show more…
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