What is the pH of the solution in the cathode compartment of the following cell if the measured cell potential at 25 ∘C is 0.58 V ? Zn(s)∣∣Zn2+(1M)∣∣∣∣H+(?M)∣∣H2(1atm)|Pt(s)
Added by Sylvia P.
Step 1
58 V Standard cell potential (E°cell) = 0.76 V Number of electrons transferred (n) = 2 Using the Nernst equation: Ecell = E°cell - (0.0592/n) * log([Zn2+]/[H+]) 0.58 = 0.76 - (0.0592/2) * log(1/[H+]) 0.18 = 0.0296 * log(1/[H+]) 6.08 = log(1/[H+]) [H+] = 10^(-6.08) Show more…
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