What is the root mean square speed of a molecule of oxygen at a temperature of 27°C? Given that mass of an oxygen molecule is 5.31x10^-26 kg and Boltzmann constant k=1.38x10^-23 J/K. 517 m/s 484 m/s 145 m/s 102 m/s
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The conversion formula is \(T(K) = T(°C) + 273.15\). Given the temperature is 270°C, the conversion is \(270 + 273.15 = 543.15 K\). Show more…
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