00:01
Here we have two points, negative 3 .15, comma 8 .25, and 6 .85, comma, negative 4 .25.
00:10
And we're going to find the slope of a line that passes through these two points.
00:13
So the equation to find the slope of a line passing through two points is m, which represents slope, equals y2 minus y1 over x2 minus x1.
00:24
I'm going to label my points as my x1, y1, and my x2, y2.
00:30
It doesn't matter which ones are your ones and twos.
00:33
What matters is that you keep your x1 and y one within the same ordered pair, and your x2 and y2 have to be in the same ordered pair.
00:40
And now we can substitute.
00:41
Y2 is negative 4 .25 minus y1, which is 8 .25, over x2, which is 6 .85, minus x1, which is negative 3 .15.
00:54
Negative 4 .25 minus 8 .25 is negative 12 .5.
01:03
Over 6 .85 minus a negative.
01:07
So i've got this minus a negative here that changes to positive.
01:10
So plus 3 .15 equals negative 12 .5 over 6 .85 plus 3 .15 is 10...