What is the surface temperature of a distant star having a peak wavelength of 475 nm? 6100 K 6350 K 5510 K 5630 K 6560 K
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The formula is: λmax = 0.0029/T Where λmax is in meters, T is in Kelvin, and 0.0029 is the Wien's displacement constant in m.K. Given that the peak wavelength is 475 nm, we need to convert this to meters: 475 nm = 475 x 10^-9 m = 4.75 x 10^-7 m Now we can Show more…
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