What mass of carbon dioxide will be produced when 11.6 g of butane reacts with an excess of oxygen in the following reaction? Give your answer rounded to one digit on the right of the decimal point. Do not enter the unit. 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O
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- Carbon (C) has a molar mass of 12.01 g/mol. - Hydrogen (H) has a molar mass of 1.01 g/mol. - Butane (C4H10) has 4 carbon atoms and 10 hydrogen atoms. Molar mass of C4H10 = (4 × 12.01) + (10 × 1.01) = 48.04 + 10.10 = 58.14 g/mol. Show more…
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