Question

What will be the output of the following C code? 1. #include <stdio.h> 2. 3. { 4. 5. 6. 7. 8. 9. } void main() int a[2][3] = {1, 2, 3, 4, 5}; int i = 0, j = 0; for (i = 0; i < 2; i++) for (j = 0; j < 3; j++) printf("%d", a[i][j]); 123450 12345 junk 123455 Run time error

          What will be the output of the following C code?
1. #include <stdio.h>
2.
3.
{
4.
5.
6.
7.
8.
9.
}
void main()
int a[2][3] = {1, 2, 3, 4, 5};
int i = 0, j = 0;
for (i = 0; i < 2; i++)
for (j = 0; j < 3; j++)
printf("%d", a[i][j]);
123450
12345 junk
123455
Run time error

What will be the output of the following C code?
1. #include <stdio.h>
2.
3.

4.
5.
6.
7.
8.
9.

void main()
int a[2][3] = 1, 2, 3, 4, 5;
int i = 0, j = 0;
for (i = 0; i < 2; i++)
for (j = 0; j < 3; j++)
printf("%d", a[i][j]);
123450
12345 junk
123455
Run time error

Added by Roy B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

Step 1

The rest of the elements in the array are not initialized explicitly, so they will be automatically initialized to 0 by the compiler. The nested for loop then prints out each element in the array. Show more…

Show all steps

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What will be the output of the following C code? #include <stdio.h> void main() { int a[2][3] = {12345}; int i = 0, j = 0; for(i = 0; i < 2; i++) { for(j = 0; j < 3; j++) { printf("%d ", a[i][j]); } } }