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B bölgesi 2x + y = 1, 2x + y = 4, x - 2y = 2 ve x - 2y = 3 do?rular? aras?nda kalan bölge olmak üzere iint_{B} frac{(x-2y)^{2}}{1+2x+y}dxdy integrali egin{cases} u = 2x + y \ v = x - 2y end{cases} dönü?ümü yard?m?yla a?a??daki integrallerden hangisi ile hesaplanabilir? frac{1}{3} int_{2}^{3} int_{1}^{4} v dudv frac{1}{5} int_{2}^{3} int_{1}^{4} frac{v^{2}}{1+u} dudv frac{1}{3} int_{2}^{3} int_{1}^{4} frac{u}{v} dudv frac{1}{5} int_{1}^{4} int_{2}^{3} frac{u^{2}}{1+v} dvdu frac{1}{3} int_{1}^{4} int_{2}^{3} udvdu

          B bölgesi 2x + y = 1, 2x + y = 4, x - 2y = 2 ve x - 2y = 3 do?rular? aras?nda kalan bölge olmak üzere iint_{B} frac{(x-2y)^{2}}{1+2x+y}dxdy integrali egin{cases} u = 2x + y \ v = x - 2y end{cases} dönü?ümü yard?m?yla a?a??daki integrallerden hangisi ile hesaplanabilir? frac{1}{3} int_{2}^{3} int_{1}^{4} v dudv frac{1}{5} int_{2}^{3} int_{1}^{4} frac{v^{2}}{1+u} dudv frac{1}{3} int_{2}^{3} int_{1}^{4} frac{u}{v} dudv frac{1}{5} int_{1}^{4} int_{2}^{3} frac{u^{2}}{1+v} dvdu frac{1}{3} int_{1}^{4} int_{2}^{3} udvdu
        
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B b   #246;lgesi 2x + y = 1, 2x + y = 4, x - 2y = 2 ve x - 2y = 3 do?rular? aras?nda kalan b   #246;lge olmak    #252;zere iintB frac(x-2y)^21+2x+ydxdy integrali egincases u = 2x + y  v = x - 2y endcases d   #246;n   #252;?   #252;m   #252; yard?m?yla a?a??daki integrallerden hangisi ile hesaplanabilir? frac13 int2^3 int1^4 v dudv frac15 int2^3 int1^4 fracv^21+u dudv frac13 int2^3 int1^4 fracuv dudv frac15 int1^4 int2^3 fracu^21+v dvdu frac13 int1^4 int2^3 udvdu

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Transcript

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00:03 The integral is x minus 2y squared over 1 plus 2x plus y dx dy.
00:14 Region is b.
00:20 U equals 2x plus y.
00:22 V equals x minus 2y.
00:30 Equation 2x plus y equals 1 becomes u equals 1.
00:42 2x plus y equals 4 becomes u equals 4.
00:52 X minus 2y equals 2 equals v equals 2.
01:01 X minus 2y equals 3 is v equals 3.
01:11 You must calculate the jacobian.
01:18 Jacobian is the partial of x with respect to u and then v along the first row and then partial of y with respect to u partial of y with respect to v.
01:38 In order to find this we must find x and y in terms of u and v.
01:46 Okay so then 2u plus v divided by 5 is going to equal x...
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