Question

Wheel Spinner The wheel spinner shown here is spun twice. Find the sample space, and then determine the probability of the following events. (Figure can't copy) a. An odd number on the first spin and an even number on the second spin (Note: 0 is considered even.) b. A sum greater than 4 c. Even numbers on both spins d. A sum that is odd e. The same number on both spins

          Wheel Spinner The wheel spinner shown here is spun twice. Find the sample space, and then determine the probability of the following events.
(Figure can't copy)
a. An odd number on the first spin and an even number on the second spin (Note: 0 is considered even.)
b. A sum greater than 4
c. Even numbers on both spins
d. A sum that is odd
e. The same number on both spins

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Added by Lisa M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Chapter 4

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Solved by Expert Samriddhi Singh

02/19/2023

Step 1

Since the figure of the wheel spinner cannot be copied, let's assume the wheel spinner has numbers 0, 1, 2, and 3. This means when the wheel is spun, it can land on any of these four numbers. The sample space for two spins can be represented as pairs of numbers Show more…

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Wheel Spinner The wheel spinner shown here is spun twice. Find the sample space, and then determine the probability of the following events. (Figure can't copy) a. An odd number on the first spin and an even number on the second spin (Note: 0 is considered even.) b. A sum greater than 4 c. Even numbers on both spins d. A sum that is odd e. The same number on both spins

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Transcript

00:01 Hello everyone.

00:02 So in this question it is given that a wheel spinner shown in the question is spun twice.

00:09 We have to find the sample space and determine the probability of the following events.

00:13 So here we first see that the outcomes are 0, 1, 2, 3 and 4.

00:23 That is the total of n equals to 5 outcomes.

00:29 So total possible cases becomes 5 multiplied by 5.

00:42 Why? because it is spun 2 times.

00:45 So this becomes 25.

00:47 Now coming to part a, an odd number on the first spin and an even number on the second spin.

00:59 Odd, then even.

01:04 Right? this is the combination.

01:06 So the sample space becomes 1 .0, 1 2, 14.

01:23 3 .3, 3 2 and 3 4.

01:31 Talking about probability, so this is our event capital a.

01:38 So, probability of capital a becomes total favorable or 6 divided by total possible is 25.

01:49 Next, a sum greater than 4.

01:56 Let this said be b, which is such that sum is greater than 4.

02:03 So first we'll write this sum.

02:05 Sample space.

02:08 So sample space becomes, now if sum is greater than 4, then it would be 5, 6, 7 or 8.

02:17 The maximum could be 8...

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