00:01
Hi, today we are solving the question in which we are given with sum that is as summation of n is equal to 3 to infinity minus 1 raised to the power n divided by n into log n whole raised to the power 4.
00:22
Similarly, the partial sum here is n so here n is given as 9.
00:31
So from here s9 is given as summation of summation till 9 minus 1 raised to the power n, n into log n whole raised to the power.
00:51
So here we have to find the error.
00:54
So we know that s minus s n is small than equal to a .n plus 1.
01:03
Similarly, error is small than equal to a .n plus 1.
01:11
So for s9, the summations will be sigma 9, n is equal to 3 minus 1, raised to the power n, n into log n whole raise to the power 4.
01:29
So on putting the values here, we get minus infinity plus minus 4...