00:01
Hi, in this question we are given that in an experiment we are having 3 .10 gram of cocl 2 .6h2o.
00:07
It reacts with sodium carbonate, that is, n .a2, co3, in order to produce the precipitate of cobalt second carbonate, that is coco3, along with this, there is formation of 6h2o and 2 moles of nacl.
00:20
We are asked to calculate the mass of n .a .2 .o .3, that is sodium carbonate, required for complete precipitation of coco3.
00:30
Also we need to calculate the moles of cocl2 .6 h2o that are used in this reaction.
00:37
First of all we will calculate moles of co, cl2 6h2o.
00:43
It will be equal to mass over molar mass.
00:47
We can substitute the values here.
00:49
In this manner, now we can eliminate the common unit gram from here and on solving we are getting moles of cocl2 .6 h2o equals to 0 .0130 mole...