00:01
Okay, we need to compute the minimum needed e b n 0 which is energy per bit to noise power spectral density.
00:07
So e b n o n 0 e b is evaluated as 10 multiplied by log 10 multiplied by s divided by 10.
00:23
So then s is said to be signal power and n is said to be noise power.
00:28
So c value will be evaluated as b wherein we subtract, sorry b multiplied by log 2 which is 10 multiplied by 1 wherein we add s &r.
00:43
C is said to be channel capacity, b is bandwidth and s &r is signal to noise ratio.
00:48
So rearranging for evaluating s &r value.
00:52
So it is 2 to the power c divided by b wherein we add 1 putting in the values.
00:59
2 to the power 28 ,000 divided by 3 ,100 wherein we subtract 1, sorry when we subtract the value.
01:11
So equating it we get the value to be approximately 10 .18 then e b n o db value is then evaluated as 10 multiplied by log 10 multiplied by 10 .18.
01:37
So the value then is approximately 10 .11 db...