In this equation, \( \mathrm{O}_{2} \) is being reduced and \( \mathrm{Fe}^{2+} \) is being oxidized. The reduction half-reaction is \( \mathrm{O}_{2} + 4\mathrm{H}^{+} + 4\mathrm{e}^{-} \rightarrow 2\mathrm{H}_{2}\mathrm{O} \) and the oxidation half-reaction is
Show more…