00:01
Hi, here in this given problem, two lenses, two thin lenses, both are converging, are being used to form the image of an object.
00:16
So these are the two lenses.
00:23
The first one, having a focal length f1.
00:28
And then the second one, having a focal length f2 and they are hands.
00:40
Having a gap between them s.
00:46
So, first of all, the height of object kept in front to the left of the first lens, h -o, this is 1 .60 centimeter, and the distance of the object from the first lens, do1.
01:09
And using sign convention this is minus 56 .0 centimeter focal length of the first lens this is 40 .0 centimeter and that of the second lens this is 60 .0 centimeter gap between them this is 300 centimeters so first of all in order to find the position of the image with respect to the first for the first lens using thin lens formula 1 by d i 1 image distance for the first lens minus 1 by d o 1 object distance for the first lens is equal to 1 by f1 then plugging in all the known values this is 1 by d i 1 minus 1 by minus 56 is equal to 1 by 40.
02:16
So 1 by d .i.
02:18
1, that will be equal to 1 by 40 minus 1 by 56...