00:01
Okay, so we're doing chapter 34 problem 41.
00:04
So this one's going to be talking about the combination of lenses, as we can see here.
00:08
So we start out with an object of 1 .2 centimeters tall, and we place it 50 centimeters to the left of the converging lens.
00:20
So let me just place that right here.
00:23
So call that s1 equals 50 centimeters.
00:28
And this lens, this first lens is a focal length of 40 centimeters.
00:33
So f1 equals 40.
00:37
Okay, so we have a second converging lens with a focal length of 60 centimeters, placed 300 centimeters to the right of the first one.
00:48
Awesome.
00:51
So, cool.
00:53
So part a.
00:54
We want to figure out the location and height of the image formed from the first lens.
00:59
Cool.
01:00
So this is, we can rearrange the thin lens equation as we do always solve for what the image location is.
01:10
I'll call it s1 because it's from the first lens.
01:13
So s1 prime is s1 f1 over s1 minus f1.
01:20
So let's start plugging that in.
01:22
So this is 50 times 40 over 50 minus 40.
01:29
And we should see that that comes out to being 200.
01:32
Centimeters.
01:36
So let's go ahead and mark this as i1 and this is 200 centimeters away.
01:47
So that means this distance right here is going to be s2 and now we know it's going to be 100 centimeters.
01:54
Cool but let's finish this one part a.
01:57
So this is s1 prime.
02:01
So now we need to figure out the height...