Which of the following acids (listed with $K_a$ values) and their conjugate base should be used to form a buffer with a pH of 8.10? $pK_a = -log K_a$ HF $K_a = 3.47 imes 10^{-4}$ HCIO $K_a = 2.88 imes 10^{-8}$ $HC_7H_5O_2$ $K_a = 6.46 imes 10^{-5}$
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We can use the formula pKa = -log(Ka). For HF: pKa = -log(3.47 * 10^(-4)) ā 3.46 For HClO: pKa = -log(2.88 * 10^(-8)) ā 7.54 For HC2H3O2: pKa = -log(6.46 * 10^(-5)) ā 4.19 Now, we need to choose the acid with a pKa value closest to the desired pH of 8.10. Show moreā¦
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Which of the following acids (listed with Ka values) and their conjugate base should be used to form a buffer with a pH of 8.10? pKa = -log Ka HF Ka = 3.47 x 10^-4 HClO Ka = 2.88 x 10^-8 HC7H5O2 Ka = 6.46 x 10^-5
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Which of the following acids (listed with Ka values) and their conjugate base should be used to form a buffer with a pH of 2.34? Group of answer choices HClO2, Ka = 1.1 Ć 10-2 HIO, Ka = 2.3 Ć 10-10 HCN, Ka = 4.9 Ć 10-10 C6H5OH, Ka = 1.3 Ć 10-10 HN3, Ka = 2.5 Ć 10-5
Which of the following acids (listed with Ka values) and their conjugate base would form a buffer with a robust capacity around pH = 2.34? which of the ones that apply A) HCN, Ka = 4.9 Ć 10-10 B) HC3H3O3, Ka = 4.1 Ć 10-3 C) HF, Ka = 3.5 Ć 10-4 D) HC7H5O2, Ka = 6.5 Ć 10-5 E) HClO, Ka = 2.9 Ć 10-8
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