00:01
Okay, this problem is asking us which of these compounds is going to dehydrate the fastest when heated with acid.
00:06
Okay, so basically this problem is asking us if we heat this with acid, which one is going to form water first slash result in a carbocadion? so which one is going to form the most stable carbocadion? so let's consider if i made this first one, if i made that water, that will be oh2 with a positive charge.
00:24
And if that were to leave, we'll be left with this.
00:28
So we'd have a my methyl group still there and we'd have a secondary positive carbacadine.
00:33
Okay, that's not necessarily bad, but it would undergo further carbokadion rearrangements to eventually get it onto this position.
00:42
Okay, so we're talking about which one is going to form the fastest.
00:45
So because this is going to result in the carbocadine formation of the secondary alcohol, secondary alcohols are not the most favorable to occur.
00:53
Okay, next up, we have this one.
00:55
So this one looks pretty good because we have that.
00:58
Tertiary alcohol, if it gets heated with acid, it's going to be forming oh2 with a positive charge.
01:03
That's going to leave.
01:04
And we're going to result in the immediate formation of our tertiary carbocadine.
01:09
Okay, so that seems pretty good.
01:10
Tertiary carbacadines, we know are to be, we know them to be super stable.
01:13
So that could be a possibility.
01:15
And the next step, we have this one.
01:17
So this one, if this gets heated with acid, we're going to get my oh2 with a positive charge.
01:21
That oh2 is going to go ahead and leave.
01:23
And we're going to get my primary carbocadine.
01:26
And it's primary because the carbon in which my...