Question

Which of the following is correct answer for the choice of $\alpha$, $\beta$ and $\gamma$ (FINITE) so that $\lim_{y \to 0} \frac{e^{2y} + \alpha - (\beta + 1)y}{y^2} = \gamma$ A) $\alpha = -1$, $\beta = 3$ and $\gamma = 1/2$ B) $\alpha = -1$, $\beta = 1$ and $\gamma = 2$ C) $\alpha = -1$, $\beta = 1$ and $\gamma = 1/2$ D) $\alpha = 1$, $\beta = -3$ and $\gamma = -2$ E) $\alpha = 1$, $\beta = -3$ and $\gamma = 1/2$

          Which of the following is correct answer for the choice of $\alpha$, $\beta$ and $\gamma$ (FINITE) so that
$\lim_{y \to 0} \frac{e^{2y} + \alpha - (\beta + 1)y}{y^2} = \gamma$
A) $\alpha = -1$, $\beta = 3$ and $\gamma = 1/2$
B) $\alpha = -1$, $\beta = 1$ and $\gamma = 2$
C) $\alpha = -1$, $\beta = 1$ and $\gamma = 1/2$
D) $\alpha = 1$, $\beta = -3$ and $\gamma = -2$
E) $\alpha = 1$, $\beta = -3$ and $\gamma = 1/2$

Which of the following is correct answer for the choice of α, β and γ (FINITE) so that
limy → 0(e^2y + α - (β + 1)y)/(y^2) = γ
A) α = -1, β = 3 and γ = 1/2
B) α = -1, β = 1 and γ = 2
C) α = -1, β = 1 and γ = 1/2
D) α = 1, β = -3 and γ = -2
E) α = 1, β = -3 and γ = 1/2

Added by Elena H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Thanks for your feedback!

Which of the following is the correct answer for the choice of a, 3, and âˆš(FINITE) so that lim yâ†’0 âˆš(y^2) A) a = -1, 3 = 3 and âˆš(FINITE) = 1/2 B) a = -1, 3 = 1 and âˆš(FINITE) = 2 C) a = -1, âˆš(FINITE) = 1 and âˆš(FINITE) = 1/2 D) a = 1, 3 = -3 and âˆš(FINITE) = -2 E) a = 1, 3 = -3 and âˆš(FINITE) = 1/2