Question

Which of the following is equivalent to $\int 3x^2(x-5)dx$? $\frac{3}{4}x^4 - 5x^3 + C$ $9x^2 - 30x + C$ $x^3(\frac{1}{2}x^2 - 5x) + C$ $3x^3 - 15x^2 + C$

          Which of the following is equivalent to $\int 3x^2(x-5)dx$? 
$\frac{3}{4}x^4 - 5x^3 + C$
$9x^2 - 30x + C$
$x^3(\frac{1}{2}x^2 - 5x) + C$
$3x^3 - 15x^2 + C$

Which of the following is equivalent to ∫ 3x^2(x-5)dx?
(3)/(4)x^4 - 5x^3 + C
9x^2 - 30x + C
x^3((1)/(2)x^2 - 5x) + C
3x^3 - 15x^2 + C

Added by Leslie V.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Narayan Hari

07/22/2021

Step 1

Step 1: Distribute the 3x^2 into the (x-5) term to simplify the integral: \int 3x^2(x-5) dx = \int 3x^3 - 15x^2 dx Show more…

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Which of the following is equivalent to int 3x^(2)(x-5)dx ? (3)/(4)x^(4)-5x^(3)+C 9x^(2)-30x+C x^(3)((1)/(2)x^(2)-5x)+C 3x^(3)-15x^(2)+C 3 -x4-5x3+C 4 O 9x2-30x+C =x-5x+C O 3x3-15x2+C