0:00
Hello everyone.
00:01
So, here we have the question and the answer to this question is that the total magnification.
00:08
The total magnification is basically the product of two factors.
00:14
That is the first one is the magnification of the eyepiece, the magnification of the ocular lens as such we can say ips.
00:29
And nextly we can say this is multiplied with the objective lens.
00:36
Objective lens.
00:39
Now here the magnification of the ips.
00:43
Suppose this is m and suppose this is o.
00:47
Okay.
00:48
So, m1 is equal to 10x.
00:52
So for 4x, for 4x, we can say that the total magnification, would be total magnification would be 4 into 10 that is equal to 40 let the total magnification be tm so this is basically the tm clear now the diameter of diameter of the field of vision for this 4x is so the diameter for this 4x is equal to 4 .5 mm and we know that 1mm is equal to thousand mu m.
01:37
And therefore we can say that this will be equals to 4 .5 into 10 power 3 mu m.
01:44
So this will be equal to 4 5 double 0 mu m.
01:50
Okay...