00:01
The answer to the question is as follows.
00:02
So first let us write the newly synthesized strand.
00:08
So if we write it, it will be, let's say from 5 prime, t a, c, g, g, g, a, c t, g, and 4 times a, 3 prime.
00:22
So if this is newly synthesized strand, then the template will be, template will be from 3 prime to 5 prime and it will be a t g c c t then g g a c and t t t t now there are two scenarios in this case for the repair mechanism let's say in the first case the problem is 5 prime t a t g g g g a c t g a and here is a loop formation with a and a so in this case the newly synthesized strand loops out.
01:06
Then what will happen? let's say template is the same as the test.
01:13
In this case again in the 5 prime, let's say t, a c, g, g, g, a, c t, g, a, c t, a.
01:22
And here will be one loop will be added.
01:26
Because from here one nucleotide was removed, here one will be added leading to a, a, c, g, t, g, c t, t c to the new strand.
01:39
So here one nucleotide is added, which is called as the the resulted new strand has an extra nucleotide a...