00:01
In this question, we have been asked to identify the sample with the greatest number of atoms present in it.
00:18
The first sample given to us here is 100 grams of lead.
00:23
100 grams of lead.
00:25
Let us calculate how many atoms are present in 100 grams of lead.
00:29
See we know that the atomic mass the atomic mass of the element lead is 207 .2 grams.
00:40
207 .2 grams.
00:43
So from this we can clearly say that 207 .2 grams of lead, that is, p .b, will contain avogadro number of atoms, that is it will have 6 .02 multiplied by 10 raised to the power 23 atoms.
01:04
So many atoms will be present in 207 .2 grams of lead.
01:09
Therefore, we can say that 100 grams of lead will contain the number of atoms as 6 .02 multiplied by 10 raised to the power 23.
01:22
This will be divided by the atomic mass that is 207 .2.
01:27
And this whole will be multiplied by 100.
01:30
On solving it, we will finally get the total number of atoms present in 100 grams of lead as 2 .95 multiplied by 10 raised to the power 23.
01:43
The next sample given is 2 .0 moles of argon.
01:50
We have to calculate the number of atoms in it.
01:52
See, we know that 1 mole of the element argon, which is a monoatomic gas, will contain avogadro number of atoms.
02:01
So it will have 6 .02 multiplied by 10 raise to the power 23 number of atoms.
02:08
So we have to calculate the number of atoms in 2 moles.
02:11
So we can clearly say that 2 moles of argon will have 6 .02 multiplied by 10 raise to the power 23 this whole will be multiplied by 2 and so on calculating this comes out as 12 .04 multiplied by 10 raised to the part 23 atoms so so many atoms will be present in 2 moles of argon the next sample given contains 0 .10 moles of the element iron which is a metal so we know that the atomic mass of iron is 56.
02:56
We can clearly say that 1 moles of the element iron will contain avogadro number of atoms, that is it will have 6 .02 multiplied by 10 raised to the power 23 atoms.
03:11
So therefore we can clearly say that 0 .1 moles of iron will contain 6 .02 multiplied by 10 raise to the power 23.
03:25
This will be multiplied by 0 .1...