Question

Which of the following scenerios fits all of the criteria for the two-source interference equations to be valid? An observer stands on a road that runs five kilometers away from the two synchronized transmitting towers for a radio station.Light from an incandescent bulb passes through a screen with two narrow slits onto an observation screen directly behind it.An observer stands on a road far away from two neighboring radio towers for different radio stations.An observer is standing far away from two red LED signal lights. Why are the two-source interference equations not valid for light from an incandescent bulb that passes through a screen with two narrow slits onto an observation screen directly behind it? not monochromatic sources incoherent sources observed from a distance similar to or smaller than the separation between the sources 1 only 2 only 3 only 1 and 2 only 1 and 3 only 2 and 3 only all three

          Which of the following scenerios fits all of the criteria for the two-source interference equations to be valid? An observer stands on a road that runs five kilometers away from the two synchronized transmitting towers for a radio station.Light from an incandescent bulb passes through a screen with two narrow slits onto an observation screen directly behind it.An observer stands on a road far away from two neighboring radio towers for different radio stations.An observer is standing far away from two red LED signal lights.
Why are the two-source interference equations not valid for light from an incandescent bulb that passes through a screen with two narrow slits onto an observation screen directly behind it?
not monochromatic sources
incoherent sources
observed from a distance similar to or smaller than the separation between the sources
1 only    2 only    3 only    1 and 2 only    1 and 3 only    2 and 3 only    all three

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Added by Francisco Javier L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Khoobchandra Agrawal

09/04/2020

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The two-source interference equations are typically valid when the sources are coherent (i.e., they maintain a constant phase relationship), monochromatic (i.e., they emit light of a single wavelength), and the distance from the sources to the observation point is Show more…

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Which of the following scenerios fits all of the criteria for the two-source interference equations to be valid? An observer stands on a road that runs five kilometers away from the two synchronized transmitting towers for a radio station.Light from an incandescent bulb passes through a screen with two narrow slits onto an observation screen directly behind it.An observer stands on a road far away from two neighboring radio towers for different radio stations.An observer is standing far away from two red LED signal lights. Why are the two-source interference equations not valid for light from an incandescent bulb that passes through a screen with two narrow slits onto an observation screen directly behind it? not monochromatic sources incoherent sources observed from a distance similar to or smaller than the separation between the sources 1 only 2 only 3 only 1 and 2 only 1 and 3 only 2 and 3 only all three

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00:01 Hello everyone here there are two sources of light which generating the light of any wavelength but monogromatic in the visible range they are 2 .04 micrometer apart there is an observer in the line joining two sources and from any source observer is 2 .04 micrometer away we have to in the part a we have to find the wavelengths of light for which observer will see the bright light, that is constructive interference will take place.

00:40 In second part, how would your answer be affected if two sources were not in the line of observer but we are still arranged so that one source is 2 .04 micrometer farther away from observer than other.

00:58 Third part, what should be the wavelength of visual light for destructive interference to take place at the post? of observer.

01:08 Let us start solving it.

01:14 At a we are solving as we know for constructive interference part difference must be m into lambda.

01:46 Here m may be 0 plus minus 1 plus minus 2.

01:53 Here part difference between the two sources is 2 .04 micrometer and that should be equal to m into lambda.

02:07 So it will be 2 .04 micrometer upon m.

02:23 Or you may write 2040 nanometer upon m.

02:37 Now if we substitute m 1, the lambda will be 204040 which is more than the range.

02:46 If we substitute 2, it is more than the range.

02:47 If we substitute 2, it is more than the range.

02:49 If we substitute m is equal to 3.

02:53 Lambda 3 you will get 2040 just only trial error method you should keep on substituting the value you will get the answer so it will be 646 80 nanometer lambda 42040 upon 4 so it will be 510 nanometer and if wavelength to be sorry m to be 510 nanometer and if wavelength to be sorry m to be 5.

03:43 You will get wavelength to be 408 nanometer.

03:51 So these are the three wavelengths possible...

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