Which statement describes a reaction at 298 K if ΔH = 31 kJ/mol, ΔS = 0.093 kJ/(mol-K)? A. Gibbs free energy is negative. B. It is at equilibrium. C. It is exothermic. D. It is not spontaneous.
Added by Gabrielle L.
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Given: ΔH = 31 kJ/mol ΔS = 0.093 kJ/(mol-K) T = 298 K Now, let's calculate ΔG: ΔG = 31 kJ/mol - (298 K * 0.093 kJ/(mol-K)) ΔG = 31 kJ/mol - 27.714 kJ/mol ΔG = 3.286 kJ/mol Since ΔG is positive, the reaction is not spontaneous. Show more…
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