00:01
Hello, here we have to solve the following problem.
00:02
In equation 43 we have to rank the forces.
00:09
So let's write down formula for each force.
00:14
Let's start with the case afa.
00:16
Here this force is g times m1 m2 over 2r squared.
00:26
Here m1 is 4 3rd pi r cubed density and m1 equals to m2.
00:56
Let's simplify this.
00:58
That's gonna be 4 over 9 pi r cubed density squared over 1 over rho squared.
01:09
Now let's calculate the force and the key speed.
01:17
And now the distance is 2r actually 4r squared.
01:24
Now let's determine m1 and m2 which are the same.
02:07
Now let's calculate it.
02:34
And now let's determine, so as we can notice fb is greater than fa.
02:41
And now let's determine fc.
02:44
The distance now is 4r which has to be squared...