00:01
Hello everyone.
00:01
So here we are given that there is ideal gas which is slowly compressed like this.
00:07
This shows the isothermal process.
00:09
This ad shows iso -volumetric process and this b -d shows isobaric process.
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The constant pressure is of 2 atm.
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It is compressed from 10 to 2.
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We have to find a total work done by the gas in the process b -d.
00:34
Then we have to find that the total heat flow in the process.
00:39
So let us start with part a.
00:42
Now let us start, we have the first work done that is in the isobaric region.
00:54
This is equal to pressure multiplied by the difference in volume since here the pressure is constant.
01:02
Therefore this is equal to 2 atm.
01:07
That means 2 multiplied by 1 .01 multiplied by 10 raised to the par 5 pascal's 2 minus 10 multiplied by 10 raised to the power minus 3 since it is given in liters and joules now so work done is minus 1 ,616 joules.
01:31
Now w2 that is the work done in da which is is isocholic process.
01:40
It will be 0 joules.
01:42
Since the change in volume is 0.
01:47
Hence, the total work done is equal to w1 plus w2...