00:01
This question is going to take a look at ionic equations and predicting and kind of looking at whether precipitates will be formed from the equations.
00:13
So we're asked to combine sodium chloride.
00:16
So we've got sodium and chloride ions floating around in solution with lead acetate.
00:21
Lead in its 2 plus form acetate ion looks like this.
00:26
We need two of them to balance the reaction out properly.
00:30
And the products that would form in terms of a possible precipitate here would be lead to chloride.
00:38
So it would look like this.
00:41
And this indeed would be a solid because lead chloride or lead to chloride is not very soluble in water.
00:48
And we see that that presence of needing two chloride ions to balance the reaction out also means we have to do a little shifting over here on this side.
00:59
Make sure that we have a proper balance of our ions and charges on the left side as well.
01:07
And in addition to that lead chloride that forms, we've got a couple of spectator ions that are floating around in solution.
01:16
That never come are part of the process of interacting here.
01:21
They only furnish for us the ions that we need.
01:24
Those are going to be my sodium ions and those acetate ions.
01:29
So i'll write the acetate down here.
01:33
These are my spectator ions.
01:36
And although they're part of the overall solution chemistry, they're not part of forming the ultimate solid compound.
01:45
And as a result, they appear the same way before the reaction as they do after the reaction.
01:53
And sometimes what you're asked to do is write a net reaction for a process like this, where you take only the ions that were involved in making your ultimate product and combine them, and do not show your spectator ions.
02:09
So a net reaction for this would look something like the lead 2 plus come together with two chlorides to produce that solid lead 2 chloride compound.
02:24
The next reaction takes a look at combining potassium sulfate, so potassium ions, sulfate ions with strontium iodide.
02:32
So here are those ions.
02:35
And we do see the presence of a sulfate with strontium would form for us an insoluble strontium sulfate compound overall.
02:50
And that would be the solid that's produced here...