00:01
Hello everyone, in this question we have to write the equation of quadratic graph which is mentioned in the question.
00:15
We are given with x -intercept as minus 3, 0 and minus 1, 0 and y -intercept as 0, minus 2.
00:37
So using this let us form the quadratic equation.
00:42
So to write the quadratic equation we can write it will be of the form y is equal to ax square plus bx plus c.
00:52
So using the above values that is y -intercept we can write y is equal to ax square plus bx minus 2 equal to 0.
01:07
Now we are given with the x -intercept so given that minus 3, 0 and minus 1, 0.
01:19
So taking this equation number 1 we can put these values and find out the equation using the two given points.
01:31
So now using the given point we can represent we can solve in 1.
01:41
So the equation 1 will become 9a minus 3b minus 2 equal to 0 as well as we have minus 1, 0.
01:52
So using that point we will get a minus b minus 2 equal to 0.
01:57
So we can represent this equation as 9a minus 3b minus 2 minus 3 into a minus b minus 2 equal to 0...