Question

Write an equation in point-slope form and slope-intercept form for the line passing through $(-2,-6)$ and perpendicular to the line whose equation is $x-3 y+9=0 .$ (Section 1.5 Example 2 )

Name: Write an equation in point-slope form and slope-intercept form for the line passing through (-2,-6) and perpendicular to the line whose equation is x-3 y+9=0 . (Section 1.5 Example 2 )
Uploaded: 2021-09-05T11:00:02-08:00
Duration: 2 min 31 s
Channel: Abhishek Kumar
Description: Write an equation in point-slope form and slope-intercept form for the line passing through (-2,-6) and perpendicular to the line whose equation is x-3 y+9=0 . (Section 1.5 Example 2 )

          Write an equation in point-slope form and slope-intercept form for the line passing through $(-2,-6)$ and perpendicular to the line whose equation is $x-3 y+9=0 .$ (Section 1.5 Example 2 )

Added by -Scar M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Abhishek Kumar

09/05/2021

Step 1

To find the slope of the given line, we need to rearrange the equation into slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. So, let's solve for $y$: $$x - 3y + 9 = 0$$ $$-3y = -x + 9$$ $$y = \frac{1}{3}x - Show more…

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Write an equation in point-slope form and slope-intercept form for the line passing through $(-2,-6)$ and perpendicular to the line whose equation is $x-3 y+9=0 .$