Question

5. Write an equilibrium expression ($K_c$) for the equation: 4 HCl(g) + O$_2$(g) ? 2 H$_2$O(l) + 2 Cl$_2$(g) $\bigcirc K_c = \frac{[Cl_2]^2}{[HCl]^4}$ $\bigcirc K_c = \frac{[Cl_2]}{[HCl][O_2]}$ $\bigcirc K_c = \frac{[Cl_2]^2}{[HCl]^4[O_2]}$ $\bigcirc K_c = \frac{[H_2O][Cl_2]^2}{[HCl]^4[O_2]}$

          5. Write an equilibrium expression ($K_c$) for the equation:
4 HCl(g) + O$_2$(g) ? 2 H$_2$O(l) + 2 Cl$_2$(g)
$\bigcirc K_c = \frac{[Cl_2]^2}{[HCl]^4}$
$\bigcirc K_c = \frac{[Cl_2]}{[HCl][O_2]}$
$\bigcirc K_c = \frac{[Cl_2]^2}{[HCl]^4[O_2]}$
$\bigcirc K_c = \frac{[H_2O][Cl_2]^2}{[HCl]^4[O_2]}$

5. Write an equilibrium expression (Kc) for the equation:
4 HCl(g) + O2(g) ? 2 H2O(l) + 2 Cl2(g)
◯ Kc = ([Cl2]^2)/([HCl]^4)
◯ Kc = ([Cl2])/([HCl][O2])
◯ Kc = ([Cl2]^2)/([HCl]^4[O2])
◯ Kc = ([H2O][Cl2]^2)/([HCl]^4[O2])

Added by Kathleen P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/28/2023

Step 1

Step 1: Identify the products and reactants in the equation: 4 HCl(g) + O2(g) ⇌ 2 H2O(l) + 2 Cl2(g) Show more…

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Write an equilibrium expression (Kc) for the equation: 4HCl(g) + O2(g) ⇌ 2H2O(l) + 2Cl2(g) Kc = ([Cl2]^2) / ([HCl]^4) Kc = (Cl2) / (HCl)(O2) Kc = ([Cl2]^2) / ([HCl]^4)(O2) Kc = [H2O]([Cl2]^2) / ([HCl]^4)(O2) Write an equilibrium expression (Kc) for the equation: 4 HCl(g) + O2(g) ⇌ 2 H2O(l) + 2 Cl2(g) Kc = [Cl]2 / [HCl]4 Kc = [Cl] / [HCl][O] Kc = [Cl] / [HCl]4[O] Kc = [H2O][Cl]2 / [HCl]4[O]