Write an integral giving the area of the surface obtained by revolving the curve about the x-axis. (Do not evaluate the integral). y = 4/x, 1 ? x ? 5 ? 8? ?_1^5 (?(x^4 + 16) / x^3) dx ? 2? ?_1^5 (4/x) (1 + (-4/x^2)^2) dx ? 8? ?_1^5 x^3 ?(x^4 + 16) dx ? 2? ?_1^5 (?(x^4 - 16) / x^2) dx
Added by Darren F.
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Step 1: The given curve is y = 4/x, where 1 ≤ x ≤ 5. Show more…
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