00:01
That you would expect from reaction of each of the following archa halides with one n a plus dash and s c h and the second part and n a plus and o h so we have a part one and part two for every question so for a this is our a it's actually cyclo it's cyclothin so for cyclone which is is a primary acolyte.
00:32
The s -ch -3, which comes from this compound, is a strong nucleophile and a weak base.
00:41
Therefore, we can expect an s -n -2 reaction, which will give ethyth and sulfane.
00:46
And then this is the reaction, and this is the product, which is either methyl sulfane.
00:52
And then now we're going on to raminfica 2 or part 2 of a.
00:56
Still, cycloethane, which is a primary alcohol al -halkal al -hylide.
01:01
And then now it's reacting to the nitroxide, which is a strong base.
01:06
So the primary alcoholites favor substitution reaction.
01:09
So xn2 will give ethanol.
01:11
So it's going to be a substitution reaction.
01:14
And then this reaction results to the formation of ethanol.
01:18
And this is the product.
01:19
This is the product ethanol.
01:22
Now we move on to b.
01:25
So in b, we have 2 -chloro2 methyl butane, actually.
01:30
Sorry for the spelling.
01:31
Which is a tertiary alkalolary so reacting it with the s -ch -3 from that sodium s -ch -3 compound which is a strong nitrophile and a weak base the s -1 reaction will give a methyl tetan sulfane and this is shown in this reaction here so this is the reactant and these are the reactants and this is the reaction so it gives us this product and sodium chloride.
02:08
Part 2 now we're moving on to part 2.
02:10
Again, since it's reacting now with sodium hydroxide, which is a strong base.
02:18
In the presence of strong spaces, tertiary alcohol halides will undergo e2 elimination reaction...