00:01
For this problem, we need to write the product that you would expect from the reaction of each of the following alkyl halides.
00:09
So for part a, for number one, we'll have ch3, ch2, cl plus na positive and s, ch3 minus.
00:29
And that will go to ch3, ch2s, ch3 plus in a cl.
00:42
For two, whoops, it'll be ch3, ch2 cl plus na positive oh and that will leave us with ch3, ch2oh plus sodium chloride.
01:01
For part b, part one of part b we have cl bonded to carbon c h2 ch3 ch3 and then ch3 plus in a positive and s ch3 minus and that reacts and gives you a methyl attached to a carbon double bonded to chchc.
01:36
C .h3 plus h2c double bond it to carbon, which is bonded to c .h2.
01:49
C .h .3, which is wanted to c .h .3.
01:53
And you have plus h .s.
01:57
C .h .3 plus n.
02:00
A.
02:00
C .l.
02:04
Excuse me.
02:04
And then for part two, for part b, you have c .l...