00:01
In this question, we are given a complex number, negative 1 minus i, and we are asked to rewrite this number in trigonometric form.
00:09
First of all, let's recall what is trigonometric form of a complex number.
00:13
We can rewrite a complex number as r times cos phi plus i sine fie.
00:23
Finding r is easy, r is just a length of our complex number, and this is just a square root of a squared plus b squared.
00:33
In our case, a is negative 1 and b is also negative 1, so it's going to be square root of 2.
00:41
Therefore, our complex number should be equal to square root of 2 times negative 1 minus i must be equal to square root of 2 times cos -fee plus i -sign fee.
00:58
Now let's factor out square root of 2 out of our number.
01:02
We're going to get square root of 2 times negative 1 over square root of 2 minus 1 over square root of 2 times i we can write this as square root of 2 times negative square root of 2 over 2 minus square root of 2 over 2...