Question

\int 5x(\sqrt{x} - x^2)dx = \\ (A) \frac{15\sqrt{x}}{2} - 15x^2 + C \\ (B) 5x - \frac{5x^4}{4} + C \\ (C) 2x^{5/2} - \frac{5x^4}{4} + C \\ (D) \frac{25x^{5/2}}{2} - \frac{5x^4}{4} + C \\ (E) \frac{5x^{7/2}}{3} - \frac{5x^6}{6} + C

          \int 5x(\sqrt{x} - x^2)dx = \\
(A) \frac{15\sqrt{x}}{2} - 15x^2 + C \\
(B) 5x - \frac{5x^4}{4} + C \\
(C) 2x^{5/2} - \frac{5x^4}{4} + C \\
(D) \frac{25x^{5/2}}{2} - \frac{5x^4}{4} + C \\
(E) \frac{5x^{7/2}}{3} - \frac{5x^6}{6} + C

∫5x(√(x) - x^2)dx =

(A) (15√(x))/(2) - 15x^2 + C

(B) 5x - (5x^4)/(4) + C

(C) 2x^5/2 - (5x^4)/(4) + C

(D) (25x^5/2)/(2) - (5x^4)/(4) + C

(E) (5x^7/2)/(3) - (5x^6)/(6) + C

Added by Tracy C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Kathleen Carty

05/28/2022

Step 1

Step 1: First, we need to find the antiderivative of x-x^2 with respect to x. Show more…

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Thanks for your feedback!

x-x2dx= (A) 15-15x2+C 2 54 (B) 5x- +0 4 5/2 5x4 (c) - C 4 25x5/2 5x4 (D) + C 2 4 5x7/2 5x6 (E) + C 3 6

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Question

\int 5x(\sqrt{x} - x^2)dx = \\ (A) \frac{15\sqrt{x}}{2} - 15x^2 + C \\ (B) 5x - \frac{5x^4}{4} + C \\ (C) 2x^{5/2} - \frac{5x^4}{4} + C \\ (D) \frac{25x^{5/2}}{2} - \frac{5x^4}{4} + C \\ (E) \frac{5x^{7/2}}{3} - \frac{5x^6}{6} + C

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